CH_3-C(CH_3)=CH-CH_2-CH_2-Cl xrightarrow[CaCO | vedclass

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(D) The reaction proceeds via a homoallylic carbocation intermediate.The ionization of the $C-Cl$ bond in $CH_3-C(CH_3)=CH-CH_2-CH_2-Cl$ initially for

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$2-$cyclopropylpropan$-2-$ol

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(D) The reaction proceeds via a homoallylic carbocation intermediate.The ionization of the $C-Cl$ bond in $CH_3-C(CH_3)=CH-CH_2-CH_2-Cl$ initially forms a primary carbocation,which is stabilized by the neighboring $\pi$ bond (homoallylic participation).This leads to the formation of a more stable tertiary cyclopropylmethyl cation ($2$-cyclopropylpropan-$2$-yl cation).Nucleophilic attack by $H_2O$ on this tertiary carbocation yields $2$-cyclopropylpropan-$2$-ol as the major product.

$CH_3-C(CH_3)=CH-CH_2-CH_2-Cl \xrightarrow[CaCO_3]{H_2O} (X)$
The major product $(X)$ of the above reaction is:

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The following reaction is described as:
$CH_3(CH_2)_5-CH(CH_3)-Br + OH^- \rightarrow HO-CH(CH_3)(CH_2)_5CH_3 + Br^-$

The correct pair$(s)$ of the ambident nucleophiles is (are):
$(A)$ $AgCN / KCN$
$(B)$ $RCOOAg / RCOOK$
$(C)$ $AgNO_{2} / KNO_{2}$
$(D)$ $AgI / KI$

$KI$ in acetone undergoes $S_N2$ reaction with each $P, Q, R$ and $S$. The rates of the reaction vary as:
$P: CH_3-Cl$
$Q: (CH_3)_2CH-Cl$
$R: CH_2=CH-CH_2-Cl$
$S: C_6H_5-CO-CH_2-Cl$

Which one of the following reagents is not suitable for the elimination reaction shown in the image?

The relative reactivity of
$(I)$ Benzyl chloride
$(II)$ $p$-methoxy benzyl chloride
$(III)$ $p$-Nitrobenzyl chloride
Towards $S_N^1$ reaction follows the order

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$CH_3-C(CH_3)=CH-CH_2-CH_2-Cl \xrightarrow[CaCO_3]{H_2O} (X)$The major product $(X)$ of the above reaction is: