Which of the following alcohols has the highe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The solubility of alcohols in water depends on the ability to form hydrogen bonds with water molecules. As the number of hydroxyl $(-OH)$ groups i

Vedclass · Accepted Answer

Glycerol

Vedclass · Answer

(D) The solubility of alcohols in water depends on the ability to form hydrogen bonds with water molecules. As the number of hydroxyl $(-OH)$ groups increases,the number of hydrogen bonds formed with water increases,leading to higher solubility. $A$: Secondary butyl alcohol $(C_4H_9OH)$ has $1$ $-OH$ group. $B$: Tertiary butyl alcohol $(C_4H_9OH)$ has $1$ $-OH$ group. $C$: Ethylene glycol $(HO-CH_2-CH_2-OH)$ has $2$ $-OH$ groups. $D$: Glycerol $(HO-CH_2-CH(OH)-CH_2-OH)$ has $3$ $-OH$ groups. Since glycerol has the maximum number of $-OH$ groups,it forms the most extensive hydrogen bonding with water,making it the most soluble among the given options. Therefore,the correct option is $D$.

Which of the following alcohols has the highest solubility in water?

Similar Questions

What is the order of reactivity for the reaction ${{C}_{2}}{{H}_{5}}OH + HX \xrightarrow{Zn{{X}_{2}}} {{C}_{2}}{{H}_{5}}X + {{H}_{2}}O$?

Select the odd structure out.

Methylated spirit is

$A$ compound with the molecular formula ${C_4}{H_{10}}O$ reacts with sodium and gives a carbonyl compound upon oxidation,which does not reduce Tollen's reagent. What is the original compound?

The following transformation involves a carbocation rearrangement. The carbocation is generated by protonation of the hydroxyl group,followed by the loss of water. Which bond has to migrate in the carbocation to yield the product indicated (after the deprotonation)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module