Which of the following acids would have a STR | vedclass

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(A) The strength of a conjugate base is inversely proportional to the strength of the corresponding acid.$(A)$ $H_2S$ $(pK_a \approx 7)$ is a stronger

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$2, 4, 6$

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(A) The strength of a conjugate base is inversely proportional to the strength of the corresponding acid.$(A)$ $H_2S$ $(pK_a \approx 7)$ is a stronger acid than $H_2O$ $(pK_a \approx 15.7)$,so $H_2O$ $(2)$ has a stronger conjugate base.$(B)$ Glutarimide $(3)$ has two carbonyl groups withdrawing electron density,making it a stronger acid than Piperidin$-2-$one $(4)$. Thus,Piperidin$-2-$one $(4)$ has a stronger conjugate base.$(C)$ $CH_3C \equiv CH$ $(5)$ ($sp$ hybridized carbon) is a stronger acid than $CH_3CH = CH_2$ $(6)$ ($sp^2$ hybridized carbon). Thus,$CH_3CH = CH_2$ $(6)$ has a stronger conjugate base.Therefore,the acids with stronger conjugate bases are $2, 4, 6$.

Which of the following acids would have a $STRONGER \ CONJUGATE \ BASE$?
$(A)$ $H_2S$ $(1)$ vs $H_2O$ $(2)$
$(B)$ Glutarimide $(3)$ vs Piperidin$-2-$one $(4)$
$(C)$ $CH_3C \equiv CH$ $(5)$ vs $CH_3CH = CH_2$ $(6)$

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Which of the following acids would have a $STRONGER \ CONJUGATE \ BASE$?$(A)$ $H_2S$ $(1)$ vs $H_2O$ $(2)$$(B)$ Glutarimide $(3)$ vs Piperidin$-2-$one $(4)$$(C)$ $CH_3C \equiv CH$ $(5)$ vs $CH_3CH = CH_2$ $(6)$