Which of the compounds among N_2O, NO, N_2O_3 | vedclass

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(B) substance is diamagnetic if all its electrons are paired (i.e.,no unpaired electrons,$n = 0$).$NO$ has $15$ valence electrons (odd),so it is param

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$N_2O, N_2O_3, N_2O_4, N_2O_5$

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(B) substance is diamagnetic if all its electrons are paired (i.e.,no unpaired electrons,$n = 0$).$NO$ has $15$ valence electrons (odd),so it is paramagnetic.$NO_2$ has $17$ valence electrons (odd),so it is paramagnetic.$N_2O$ has $16$ valence electrons (even),all paired,so it is diamagnetic.$N_2O_3$ has $30$ valence electrons (even),all paired,so it is diamagnetic.$N_2O_4$ has $34$ valence electrons (even),all paired,so it is diamagnetic.$N_2O_5$ has $40$ valence electrons (even),all paired,so it is diamagnetic.Therefore,the diamagnetic compounds are $N_2O, N_2O_3, N_2O_4, N_2O_5$.

Which of the compounds among $N_2O, NO, N_2O_3, NO_2, N_2O_4, N_2O_5$ are diamagnetic?

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