Which of the C - C bond is strongest? | vedclass

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(C) The strength of a $C - C$ bond depends on the percentage of $s$-character in the hybrid orbitals.Greater $s$-character leads to shorter and strong

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Formed by $sp - sp$ hybridised carbon atoms (as in alkynes)

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(C) The strength of a $C - C$ bond depends on the percentage of $s$-character in the hybrid orbitals.Greater $s$-character leads to shorter and stronger bonds.For $sp$ hybridization,$s$-character is $50\%$.For $sp^2$ hybridization,$s$-character is $33.3\%$.For $sp^3$ hybridization,$s$-character is $25\%$.Therefore,the order of bond strength is $sp - sp > sp^2 - sp^2 > sp^3 - sp^3$.

List-$I$ (molecule)	List-$II$ (hybridization,shape)
$A. XeO_3$	$I. sp^3$; pyramidal
$B. XeF_2$	$II. sp^3d$; linear
$C. XeOF_4$	$III. sp^3d^2$; square pyramidal
$D. XeF_6$	$IV. sp^3d^3$; distorted octahedral

Which of the $C - C$ bond is strongest?

Similar Questions

Methane is tetrahedral but not square planar in nature,prove it.

Which one of the following is a planar molecule?

Which of the following molecules contains $50 \%$ $p$-character in the hybrid orbitals of the $C$ atom?

Match List-$I$ with List-$II$.

List-$I$ (molecule) List-$II$ (hybridization,shape)

$A. XeO_3$ $I. sp^3$; pyramidal

$B. XeF_2$ $II. sp^3d$; linear

$C. XeOF_4$ $III. sp^3d^2$; square pyramidal

$D. XeF_6$ $IV. sp^3d^3$; distorted octahedral

Choose the correct answer from the options given below.

What is the meaning of hybridization of atomic orbitals?

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