Which of the following reaction(s) produce th | vedclass

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(B) The Saytzeff product is the more substituted,and therefore more stable,alkene formed during an elimination reaction.$A$: $CH_3CH_2CH(F)CH_3 \xrigh

Vedclass · Accepted Answer

$CH_3CH_2CH(Cl)CH_3 \xrightarrow{alc. KOH, \Delta}$

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(B) The Saytzeff product is the more substituted,and therefore more stable,alkene formed during an elimination reaction.$A$: $CH_3CH_2CH(F)CH_3 \xrightarrow{NH_2^-, \Delta}$ This reaction involves a poor leaving group $(F^-)$ and a strong base,which often leads to the less substituted alkene (Hofmann product) as the major product due to the high transition state energy for the more substituted alkene.$B$: $CH_3CH_2CH(Cl)CH_3 \xrightarrow{alc. KOH, \Delta}$ This is a standard $E2$ elimination with a small base $(OH^-)$. The major product is the more substituted alkene,$CH_3CH=CHCH_3$ (but$-2-$ene),which is the Saytzeff product.$C$: $CH_3CH(CH_3)CH(Cl)CH_3 \xrightarrow{Me_3CO^-K^+, \Delta}$ This reaction uses a bulky base $(Me_3CO^-)$. Bulky bases prefer to abstract the most accessible proton,leading to the less substituted alkene (Hofmann product) as the major product.$D$: $CH_3CH_2CH(NMe_3^+)CH_3 \xrightarrow{OR^-, \Delta}$ This is a Hofmann elimination. The bulky leaving group $(NMe_3^+)$ forces the base to abstract the most accessible proton,resulting in the less substituted alkene (Hofmann product) as the major product.Therefore,only reaction $B$ produces the Saytzeff product as the major product.

Which of the following reaction$(s)$ produce the Saytzeff product as a major product?

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