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(D) $Br_2$ in $CCl_4$ $(a)$,$Br_2$ in $CH_3COOH$ $(b)$,and alkaline $KMnO_4$ $(c)$ will react with all unsaturated compounds,i.e.,$1, 3,$ and $4$.Ammo

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Ammoniacal silver nitrate

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(D) $Br_2$ in $CCl_4$ $(a)$,$Br_2$ in $CH_3COOH$ $(b)$,and alkaline $KMnO_4$ $(c)$ will react with all unsaturated compounds,i.e.,$1, 3,$ and $4$.Ammoniacal $AgNO_3$ $(d)$ (Tollens' reagent) reacts specifically with terminal alkynes to form a white precipitate.Compound $(3)$ $(CH_3-CH_2-C \equiv CH)$ is a terminal alkyne,whereas $1$ is an internal alkyne,$2$ is an alkane,and $4$ is an alkene.Therefore,compound $(3)$ can be distinguished from $1, 2,$ and $4$ using ammoniacal $AgNO_3$.

Which is the most suitable reagent among the following to distinguish compound $(3)$ from the rest of the compounds?
$1. CH_3-C \equiv C-CH_3$
$2. CH_3-CH_2-CH_2-CH_3$
$3. CH_3-CH_2-C \equiv CH$
$4. CH_3-CH=CH_2$

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Which is the most suitable reagent among the following to distinguish compound $(3)$ from the rest of the compounds?$1. CH_3-C \equiv C-CH_3$$2. CH_3-CH_2-CH_2-CH_3$$3. CH_3-CH_2-C \equiv CH$$4. CH_3-CH=CH_2$