Which is the decreasing order of stability?(i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The correct order of stability is $(ii) > (i) > (iii)$.$(ii)$ $CH_3-CH^{+}-OCH_3$ is the most stable because the lone pair on the oxygen atom prov

Vedclass · Accepted Answer

$(ii) > (i) > (iii)$

Vedclass · Answer

(D) The correct order of stability is $(ii) > (i) > (iii)$.$(ii)$ $CH_3-CH^{+}-OCH_3$ is the most stable because the lone pair on the oxygen atom provides strong resonance stabilization ($+M$ effect) to the carbocation.$(i)$ $CH_3-CH^{+}-CH_3$ is a secondary carbocation stabilized by hyperconjugation and the inductive effect $(+I)$ of two methyl groups.$(iii)$ $CH_3-CH^{+}-COCH_3$ is the least stable because the carbonyl group $(-COCH_3)$ exerts a strong electron-withdrawing effect ($-I$ and $-M$ effects),which destabilizes the positive charge on the carbon atom.

Which is the decreasing order of stability?
$(i)$ $CH_3-CH^{+}-CH_3$
$(ii)$ $CH_3-CH^{+}-OCH_3$
$(iii)$ $CH_3-CH^{+}-COCH_3$

Similar Questions

The bond dissociation energy of the $C-H$ bond for the compounds: $(I)\ CH_3-H, (II)\ CH_3-CH_2-H, (III)\ CH_2=CH-CH_2-H, (IV)\ C_6H_5-H$ follows the order:

Among the given compounds,choose the two that yield the same carbocation on ionization.

What is the order of stability of the following carbocations?
$(X). CH_3 - \overset{\oplus}{C}H - CH_3$
$(Y). CH_3 - \overset{\oplus}{C}H - OCH_3$
$(Z). CH_3 - \overset{\oplus}{C}H - COCH_3$

How many $1,2-$ shifts take place in the following carbocation to reach the most stable form?

The geometry of the reaction intermediate in an $S_N1$ reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Which is the decreasing order of stability?$(i)$ $CH_3-CH^{+}-CH_3$$(ii)$ $CH_3-CH^{+}-OCH_3$$(iii)$ $CH_3-CH^{+}-COCH_3$