Which is the correct order for the solubility of the following compounds in $n$-octane (at identical conditions)? $I$) Cyclohexane $II$) $KCl$ $III$) $CH_3OH$ $IV$) $CH_3CN$
- A$II < III < IV < I$
- B$II < III < IV < I$ (Note: Corrected sequence based on polarity: $II < III < IV < I$)
- C$I < IV < III < II$
- D$I < III < IV < II$
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The Henry's law constant for the solubility of $N_2$ gas in water at $298 \ K$ is $1.0 \times 10^5 \ atm$. The mole fraction of $N_2$ in air is $0.8$. Calculate the number of moles of $N_2$ dissolved in $10 \ moles$ of water at $298 \ K$ and a total pressure of $5 \ atm$.
Medium
View SolutionHenry's constant (in $kbar$) for four gases $\alpha, \beta, \gamma$ and $\delta$ in water at $298 \ K$ is given below:
Gas $K_{H} \ (kbar)$ $\alpha$ $50$ $\beta$ $2$ $\gamma$ $2 \times 10^{-5}$ $\delta$ $0.5$
(Density of water $= 10^{3} \ kg \ m^{-3}$ at $298 \ K$). This table implies that:
| Gas | $K_{H} \ (kbar)$ |
| $\alpha$ | $50$ |
| $\beta$ | $2$ |
| $\gamma$ | $2 \times 10^{-5}$ |
| $\delta$ | $0.5$ |
(Density of water $= 10^{3} \ kg \ m^{-3}$ at $298 \ K$). This table implies that:
What type of solution is the $H_2$ gas in palladium?
What is the significance of Henry's Law constant $K_H$?
Easy
View SolutionHenry's law constant for $CO_{2}$ in water is $1.67 \times 10^{8} \ Pa$ at $298 \ K$. Calculate the quantity of $CO_{2}$ in $500 \ mL$ of soda water when packed under $2.5 \ atm$ $CO_{2}$ pressure at $298 \ K$.
Difficult
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