Which is not the correct relation between ent | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The fundamental relation between enthalpy $(\Delta H)$ and internal energy $(\Delta E)$ for a process at constant pressure is given by $\Delta H =

Vedclass · Accepted Answer

$\Delta H = \Delta E - P \Delta V$

Vedclass · Answer

(C) The fundamental relation between enthalpy $(\Delta H)$ and internal energy $(\Delta E)$ for a process at constant pressure is given by $\Delta H = \Delta E + P \Delta V$. Rearranging this equation gives $\Delta E = \Delta H - P \Delta V$. For gaseous reactions,the work done $P \Delta V$ is equivalent to $\Delta n_g RT$,where $\Delta n_g$ is the change in the number of moles of gaseous species. Thus,$\Delta H = \Delta E + \Delta n_g RT$ (often written as $\Delta H = \Delta E + n RT$). Therefore,the relation $\Delta H = \Delta E - P \Delta V$ is incorrect.

Which is not the correct relation between enthalpy $(\Delta H)$ and internal energy $(\Delta E)$?

Similar Questions

$A$ well-stoppered thermos flask contains some ice cubes. This is an example of a

What is the work done when a gas is compressed from $2.5 \times 10^{-2} \ m^3$ to $1.3 \times 10^{-2} \ m^3$ at a constant external pressure of $4.05 \ bar$ (in $J$)?

Fill in the blanks:
$(i)$ During the ........... process,there is no absorption or evolution of heat.
$(ii)$ The equation $\Delta G = \Delta H - T\Delta S$ was proposed by ........... .

The relation between change in internal energy $(\Delta E)$,change in enthalpy $(\Delta H)$,and work done $(W)$ is represented as:

Which of the following options consists of only intensive parameters?

Vedclass Test Series

Exam Paper Generator

Online Exam Module