Which ion in excess $NaOH$ does not form a soluble complex?

  • A
    $Cr^{+3}$
  • B
    $Zn^{+2}$
  • C
    $Al^{+3}$
  • D
    $Fe^{+3}$

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Complex $A$ has a composition of $H_{12}O_{6}Cl_{3}Cr$. If the complex on treatment with conc. $H_{2}SO_{4}$ loses $13.5\%$ of its original mass,the correct molecular formula of $A$ is :
[Given : atomic mass of $Cr = 52 \ amu$ and $Cl = 35.5 \ amu$]

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