Which ion has the least value of theoretical | vedclass

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Question

(A) The theoretical magnetic moment is calculated using the formula $\mu = \sqrt{n(n+2)} 	ext{ BM}$,where $n$ is the number of unpaired electrons.$1$

Vedclass · Accepted Answer

$Ti^{3+}$

Vedclass · Answer

(A) The theoretical magnetic moment is calculated using the formula $\mu = \sqrt{n(n+2)} 	ext{ BM}$,where $n$ is the number of unpaired electrons.$1$. For $Ti^{3+}$ $(3d^1)$: $n = 1$,$\mu = \sqrt{1(1+2)} = \sqrt{3} \approx 1.73 	ext{ BM}$.$2$. For $Co^{3+}$ $(3d^6)$: In an octahedral field,$n = 4$ (high spin) or $n = 0$ (low spin). Assuming high spin,$n = 4$,$\mu = \sqrt{4(6)} = \sqrt{24} \approx 4.90 	ext{ BM}$.$3$. For $Cr^{3+}$ $(3d^3)$: $n = 3$,$\mu = \sqrt{3(5)} = \sqrt{15} \approx 3.87 	ext{ BM}$.$4$. For $V^{3+}$ $(3d^2)$: $n = 2$,$\mu = \sqrt{2(4)} = \sqrt{8} \approx 2.83 	ext{ BM}$.Comparing the values,$Ti^{3+}$ has the least number of unpaired electrons $(n=1)$,hence it has the least magnetic moment.

List-$I$	List-$II$
$a. [Fe(CN)_{6}]^{3-}$	$i. 5.92 \ BM$
$b. [Fe(H_{2}O)_{6}]^{3+}$	$ii. 0 \ BM$
$c. [Fe(CN)_{6}]^{4-}$	$iii. 4.90 \ BM$
$d. [Fe(H_{2}O)_{6}]^{2+}$	$iv. 1.73 \ BM$

Which ion has the least value of theoretical magnetic moment?

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Which one of the following shows maximum paramagnetic character?

Match List-$I$ with List-$II$.

List-$I$ List-$II$

$a. [Fe(CN)_{6}]^{3-}$ $i. 5.92 \ BM$

$b. [Fe(H_{2}O)_{6}]^{3+}$ $ii. 0 \ BM$

$c. [Fe(CN)_{6}]^{4-}$ $iii. 4.90 \ BM$

$d. [Fe(H_{2}O)_{6}]^{2+}$ $iv. 1.73 \ BM$

Choose the correct answer from the options given below.

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