Which information below regarding this reaction is applicable?
$CH_3-O-CH_2-Cl \xrightarrow{aq. OH^-, \Delta} CH_3-O-CH_2-OH$

  • A
    It follows $S_{N}2$ pathway,because it is a primary alkyl chloride.
  • B
    It follows $S_{N}1$ pathway,because the intermediate carbocation is resonance stabilized.
  • C
    $S_{N}1$ pathway is not followed,because the intermediate carbocation is destabilised by $-I$ effect of oxygen.
  • D
    $A$ mixed $S_{N}1$ and $S_{N}2$ pathway is followed.

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Similar Questions

Given below are two statements: one is labelled as Assertion $(A)$ and the other is labelled as Reason $(R)$.
Assertion $(A):$ $R-I$ undergoes $S_N2$ reaction faster than $R-Cl$.
Reason $(R):$ Iodine is a better leaving group because of its large size.
In the light of the above statements,choose the correct answer from the options given below:

Which reaction results in the formation of a pair of enantiomers?

Which among the following is $NOT$ a feature of $S_{N}2$ mechanism?

$1-$chloro$-3-$methylbutane on reaction with zinc and dilute hydrochloric acid gives . . . . . . as the major product.

$S_{N}1$ and $S_{N}2$ products are the same (excluding stereoisomers) for which of the following compounds?

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