Which has maximum dipole moment?

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Question

(C) The dipole moment of a molecule depends on the vector sum of the individual bond dipoles. $1$. Hexachlorobenzene $(C_6Cl_6)$ is a highly symmetric

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$1,2-$Dichlorobenzene

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(C) The dipole moment of a molecule depends on the vector sum of the individual bond dipoles. $1$. Hexachlorobenzene $(C_6Cl_6)$ is a highly symmetrical molecule where all the individual $C-Cl$ bond dipoles cancel each other out,resulting in a net dipole moment of $0 \ D$. $2$. $1,3,5$-Trichlorobenzene is also highly symmetrical,and the vector sum of the three $C-Cl$ bond dipoles is $0$. $3$. $1,2$-Dichlorobenzene has two $Cl$ atoms at adjacent positions. The resultant dipole moment is given by $\mu = \sqrt{\mu_1^2 + \mu_2^2 + 2\mu_1\mu_2 \cos 	heta}$,where $	heta = 60^\circ$. Since $\cos 60^\circ = 0.5$,the dipole moment is non-zero and significant. $4$. $1,4$-Dichlorobenzene (implied by the last structure) has two $Cl$ atoms at opposite positions,so their dipoles cancel out,resulting in a net dipole moment of $0 \ D$. Therefore,$1,2$-Dichlorobenzene has the maximum dipole moment.

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