Which has a greater resistance-a 100 W bulb o | vedclass

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(B) The power rating of a bulb is given by the formula $P = V^2 / R$,where $P$ is power,$V$ is voltage,and $R$ is resistance.Assuming both bulbs are d

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$60$ $W$ bulb

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(B) The power rating of a bulb is given by the formula $P = V^2 / R$,where $P$ is power,$V$ is voltage,and $R$ is resistance.Assuming both bulbs are designed for the same voltage $V$,the resistance is inversely proportional to the power $(R = V^2 / P)$.For a $100$ $W$ bulb,$R_1 = V^2 / 100$.For a $60$ $W$ bulb,$R_2 = V^2 / 60$.Since $60  V^2 / 100$,which means $R_2 > R_1$.Therefore,a $60$ $W$ bulb has a greater resistance.

Which has a greater resistance$-$a $100$ $W$ bulb or a $60$ $W$ bulb?

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