Which gas among the following contains the ma | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The number of molecules is directly proportional to the number of moles $(n = \frac{	ext{mass}}{	ext{molar mass}})$. $I. \ n_{Ar} = \frac{13.3 \

Vedclass · Accepted Answer

$16.0 \ g$ of $CH_{4}$

Vedclass · Answer

(B) The number of molecules is directly proportional to the number of moles $(n = \frac{	ext{mass}}{	ext{molar mass}})$. $I. \ n_{Ar} = \frac{13.3 \ g}{39.9 \ g \ mol^{-1}} = 0.33 \ mol$ $II. \ n_{O_{2}} = \frac{24.0 \ g}{32 \ g \ mol^{-1}} = 0.75 \ mol$ $III. \ n_{CO_{2}} = \frac{11 \ g}{44 \ g \ mol^{-1}} = 0.25 \ mol$ $IV. \ n_{CH_{4}} = \frac{16.0 \ g}{16 \ g \ mol^{-1}} = 1.0 \ mol$ Since $CH_{4}$ has the maximum number of moles $(1.0 \ mol)$,it contains the maximum number of molecules.

Which gas among the following contains the maximum number of molecules at $STP$? (Molar masses in $g \ mol^{-1}$: $CO_{2}=44, Ar=39.9, CH_{4}=16, O_{2}=32$)

Similar Questions

Calculate the total number of electrons present in $1.4 \,g$ of dinitrogen gas.

If $3.01 \times 10^{20}$ molecules are removed from $98 \ mg$ of $H_2SO_4$,how many moles of $H_2SO_4$ are removed?

The number of gram atoms of oxygen present in $0.3 \ mol$ of $(COOH)_2 \cdot 2H_2O$ is

$A$ person adds $1.71 \ g$ of sugar $(C_{12}H_{22}O_{11})$ to sweeten their tea. How many carbon atoms are added? (Molar mass of sugar $= 342 \ g/mol$)

Assertion $(A)$: Equal moles of different substances contain the same number of constituent particles.
Reason $(R)$: Equal weights of different substances contain the same number of constituent particles.
The correct answer is

Vedclass Test Series

Exam Paper Generator

Online Exam Module