Which electron is associated with the least e | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The energy of an electron in a multi-electron atom is determined by the $(n + l)$ rule. According to this rule,an orbital with a lower $(n + l)$ v

Vedclass · Accepted Answer

$n = 4, l = 0, m = 0, s = +1/2$

Vedclass · Answer

(B) The energy of an electron in a multi-electron atom is determined by the $(n + l)$ rule. According to this rule,an orbital with a lower $(n + l)$ value has lower energy. If two orbitals have the same $(n + l)$ value,the one with the lower $n$ value has lower energy. Calculating $(n + l)$ for each option: $A: n = 3, l = 2 \implies n + l = 3 + 2 = 5$ $B: n = 4, l = 0 \implies n + l = 4 + 0 = 4$ $C: n = 4, l = 1 \implies n + l = 4 + 1 = 5$ $D: n = 5, l = 0 \implies n + l = 5 + 0 = 5$ Comparing the $(n + l)$ values,option $B$ has the lowest value of $4$. Therefore,the electron in option $B$ is associated with the least energy.

Which electron is associated with the least energy?

Similar Questions

$A$ ball of mass $0.5\, kg$ moving with a velocity of $2\, m/s$ strikes a wall normally and bounces back with the same speed. If the time of contact between the ball and the wall is $1\, ms$,the average force exerted by the wall on the ball is ........ $N$.

The work of $146 \, kJ$ is performed in order to compress one kilo mole of a gas adiabatically,and in this process,the temperature of the gas increases by $7 \, ^oC$. The gas is $(R = 8.3 \, J \, mol^{-1} \, K^{-1})$.

In context with beryllium,which one of the following statements is incorrect?

Which of the following plants are used as green manure in crop fields and in sandy soils?

If the difference between the roots of the equations $x^2 + ax + b = 0$ and $x^2 + bx + a = 0$ is the same and $a \neq b$,then:

Vedclass Test Series

Exam Paper Generator

Online Exam Module