Which of the following does **NOT** liberate | vedclass

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(C) The reaction of $Na$ metal with compounds containing acidic hydrogen atoms (like $-OH$ or $-COOH$ groups) or compounds that can form stable aromat

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Cyclooctatetraene

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(C) The reaction of $Na$ metal with compounds containing acidic hydrogen atoms (like $-OH$ or $-COOH$ groups) or compounds that can form stable aromatic anions (like cyclopentadiene) results in the liberation of $H_2$ gas.$1$. Cyclopentadiene $(C_5H_6)$ reacts with $Na$ to form the aromatic cyclopentadienyl anion $(C_5H_5^-)$,releasing $H_2$ gas.$2$. tert-Butyl alcohol $((CH_3)_3COH)$ reacts with $Na$ to form sodium tert-butoxide $((CH_3)_3CONa)$,releasing $H_2$ gas.$3$. Acetic acid $(CH_3COOH)$ reacts with $Na$ to form sodium acetate $(CH_3COONa)$,releasing $H_2$ gas.$4$. Cyclooctatetraene $(C_8H_8)$ is a non-aromatic,tub-shaped molecule. While it can react with $Na$ to form the aromatic cyclooctatetraenide dianion $(C_8H_8^{2-})$,this reaction involves the addition of electrons (reduction) rather than the liberation of $H_2$ gas.Therefore,cyclooctatetraene does not liberate $H_2$ gas.

Which of the following does $NOT$ liberate $H_2$ gas on reaction with $Na$ metal?

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Which of the following does **$NOT$** liberate $H_2$ gas on reaction with $Na$ metal?