(C) $Al_2(SO_4)_3$ on heating gives $Al_2O_3$ (white).$HgCO_3 \cdot 3Hg(OH)_2$ on heating gives $Hg$ (liquid metal).$Cu(NO_3)_2$ on heating gives $CuO

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(C) $Al_2(SO_4)_3$ on heating gives $Al_2O_3$ (white).$HgCO_3 \cdot 3Hg(OH)_2$ on heating gives $Hg$ (liquid metal).$Cu(NO_3)_2$ on heating gives $CuO$ (black/brown coloured metal oxide).$Ba(OH)_2$ on heating gives $BaO$ (white).Therefore,the correct option is $C$.