Which compound amongst the following is not a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To determine if a compound is aromatic,it must follow $H$ückel's rule: $1$. The molecule must be cyclic. $2$. The molecule must be planar. $3$. Th

Vedclass · Accepted Answer

Cyclooctatetraene

Vedclass · Answer

(C) To determine if a compound is aromatic,it must follow $H$ückel's rule: $1$. The molecule must be cyclic. $2$. The molecule must be planar. $3$. The molecule must be fully conjugated. $4$. The molecule must have $(4n + 2) \pi$ electrons,where $n = 0, 1, 2, ...$ Let's analyze each option: - $A$: Cycloheptatrienyl cation has $6 \pi$ electrons $(n=1)$,is cyclic,planar,and conjugated. It is aromatic. - $B$: Cyclopropenyl cation has $2 \pi$ electrons $(n=0)$,is cyclic,planar,and conjugated. It is aromatic. - $C$: Cyclooctatetraene has $8 \pi$ electrons. It is not planar (it adopts a tub shape) and does not follow the $(4n + 2) \pi$ rule. It is non-aromatic. - $D$: Cyclopentadienyl anion has $6 \pi$ electrons $(n=1)$,is cyclic,planar,and conjugated. It is aromatic. Therefore,the compound that is not aromatic is cyclooctatetraene.

Which compound amongst the following is not an aromatic compound?

Similar Questions

Out of benzene,$m$-dinitrobenzene and toluene,which will undergo nitration most easily and why?

Benzene is obtained by

The number of $\pi$ electrons in the following molecule is:

The correct order of reactivity towards electrophilic substitution for the compounds $(I)$ Aniline,$(II)$ Benzene,and $(III)$ Nitrobenzene is:

The number of $sp^2$ and $sp^3$ hybridised carbons in cumene,respectively,are:

Vedclass Test Series

Exam Paper Generator

Online Exam Module