Which bond is expected to be the least polar?

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(A) Bond polarity is determined by the difference in electronegativity $(EN)$ between the bonded atoms. The greater the difference,the more polar the

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$O-F$

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(A) Bond polarity is determined by the difference in electronegativity $(EN)$ between the bonded atoms. The greater the difference,the more polar the bond.Using the Pauling scale for electronegativity:$1.$ $O-F$: $|3.44 - 3.98| = 0.54$$2.$ $P-F$: $|2.19 - 3.98| = 1.79$$3.$ $Si-N$: $|1.90 - 3.04| = 1.14$$4.$ $B-F$: $|2.04 - 3.98| = 1.94$Comparing the values,the $O-F$ bond has the smallest electronegativity difference $(0.54)$,making it the least polar bond.

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