Which among the following solutions has minim | vedclass

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(D) The boiling point elevation $\Delta T_b$ is given by $\Delta T_b = i 	imes K_b 	imes m$,where $i$ is the van't Hoff factor and $m$ is the molali

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$0.05 \ m \ CaCl_2$

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(D) The boiling point elevation $\Delta T_b$ is given by $\Delta T_b = i 	imes K_b 	imes m$,where $i$ is the van't Hoff factor and $m$ is the molality. The value of $i 	imes m$ determines the magnitude of elevation.$A) \ 0.1 \ m \ NaCl: i 	imes m = 2 	imes 0.1 = 0.2 \ m$$B) \ 0.2 \ m \ KNO_3: i 	imes m = 2 	imes 0.2 = 0.4 \ m$$C) \ 0.1 \ m \ Na_2SO_4: i 	imes m = 3 	imes 0.1 = 0.3 \ m$$D) \ 0.05 \ m \ CaCl_2: i 	imes m = 3 	imes 0.05 = 0.15 \ m$Since $0.05 \ m \ CaCl_2$ has the lowest value of $i 	imes m$ $(0.15)$,it exhibits the minimum boiling point elevation.

Which among the following solutions has minimum boiling point elevation?

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