Which among the following pairs of monomers d | vedclass

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(D) Polyamides are polymers containing amide linkages $(-CONH-)$ in their backbone.$A$. Adipic acid and Hexamethylene diamine form Nylon-$6,6$,which i

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$3$-Hydroxybutanoic acid and $3$-Hydroxypentanoic acid

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(D) Polyamides are polymers containing amide linkages $(-CONH-)$ in their backbone.$A$. Adipic acid and Hexamethylene diamine form Nylon-$6,6$,which is a polyamide.$B$. Urea and Formaldehyde form Urea-formaldehyde resin,which is a thermosetting polymer,not a polyamide.$C$. Glycine and $\epsilon$-amino caproic acid form Nylon-$2$-nylon-$6$,which is a polyamide.$D$. $3$-Hydroxybutanoic acid and $3$-Hydroxypentanoic acid form $PHBV$,which is a polyester (contains ester linkages,$-COO-$).Therefore,both $B$ and $D$ do not form polyamides. However,in the context of standard chemistry questions,$PHBV$ is explicitly a polyester,making $D$ the most direct answer for a non-polyamide.

Which among the following pairs of monomers does not generate a polyamide polymer?

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The correct answer is:

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