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(A) The boiling point of isomeric alcohols depends on the extent of branching. As the branching increases,the surface area of the molecule decreases,w

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Butan$-1-$ol

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(A) The boiling point of isomeric alcohols depends on the extent of branching. As the branching increases,the surface area of the molecule decreases,which leads to a decrease in the magnitude of van der Waals forces of attraction. Consequently,the boiling point decreases with an increase in branching. The given compounds are: $A$: Butan$-1-$ol (primary alcohol,straight chain) $B$: $2-$Methylpropan$-1-$ol (primary alcohol,branched) $C$: Butan$-2-$ol (secondary alcohol,branched) $D$: $2-$Methylpropan$-2-$ol (tertiary alcohol,highly branched) Among these,$A$ (Butan$-1-$ol) is a straight-chain primary alcohol with the largest surface area,resulting in the strongest intermolecular hydrogen bonding and van der Waals forces. Therefore,Butan$-1-$ol has the highest boiling point.

Which among the following has the highest boiling point?

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