Where will a body weigh more: 1 , km above th | vedclass

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(B) The acceleration due to gravity $g$ at a height $h$ above the surface is given by $g_h = g(1 - 2h/R)$.The acceleration due to gravity $g$ at a dep

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$1 \, km$ below the surface

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(B) The acceleration due to gravity $g$ at a height $h$ above the surface is given by $g_h = g(1 - 2h/R)$.The acceleration due to gravity $g$ at a depth $d$ below the surface is given by $g_d = g(1 - d/R)$.For the same distance $h = d = 1 \, km$,we compare the reduction in gravity.At height $h$,the reduction is $2h/R$,while at depth $d$,the reduction is $d/R$.Since $2h/R > d/R$,the value of $g$ decreases more at height $h$ than at depth $d$.Therefore,the body will weigh more at a depth of $1 \, km$ below the surface of the earth.

Where will a body weigh more: $1 \, km$ above the surface of the earth or $1 \, km$ below the surface of the earth?

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