When three inductors of same inductance $L$ are connected in series and $I$ is the current passing through the circuit,the energy stored in the circuit is:

  • A
    $\frac{1}{2} L I^2$
  • B
    $\frac{3}{2} L I^2$
  • C
    $\frac{5}{2} L I^2$
  • D
    $\frac{7}{2} L I^2$

Explore More

Similar Questions

Two inductors $L_1$ and $L_2$ are connected in parallel,and a time-varying current flows as shown. The ratio of currents $i_1/i_2$ at any time $t$ is:

Three inductances are connected as shown in the figure. The equivalent inductance between $A$ and $B$ is (in $H$)

$A$ circuit contains two inductors of self-inductance $L_1$ and $L_2$ connected in series as shown in the figure. If $M$ is the mutual inductance between them,then the effective inductance of the circuit will be

Two coils of self-inductances $6 mH$ and $8 mH$ are connected in series and are adjusted for the highest coefficient of coupling. The equivalent self-inductance $L$ for the assembly is approximately: (in $mH$)

The equivalent inductance between $A$ and $B$ is equal to

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo