When the resistance R (indicated in the figur | vedclass

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(B) The circuit can be analyzed as a Wheatstone bridge. For the current through the resistor $R'$ to remain unchanged when $R$ is varied,the bridge mu

Vedclass · Accepted Answer

$100 \, \Omega$

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(B) The circuit can be analyzed as a Wheatstone bridge. For the current through the resistor $R'$ to remain unchanged when $R$ is varied,the bridge must be balanced. In the given circuit,the arms of the bridge are formed by the resistors $1 \, k\Omega$,$10 \, k\Omega$,$R'$,and $1 \, k\Omega$. For a balanced Wheatstone bridge,the ratio of resistances in opposite arms must be equal: $\frac{1 \, k\Omega}{10 \, k\Omega} = \frac{R'}{1 \, k\Omega}$ Solving for $R'$: $R' = \frac{1 \, k\Omega 	imes 1 \, k\Omega}{10 \, k\Omega} = 0.1 \, k\Omega = 100 \, \Omega$ Thus,the value of the resistor $R'$ is $100 \, \Omega$.

When the resistance $R$ (indicated in the figure below) is changed from $1 \, k\Omega$ to $10 \, k\Omega$,the current flowing through the resistance $R'$ does not change. What is the value of the resistor $R'$?

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