When the key K is pressed at time t = 0,which | vedclass

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(C) When the key $K$ is pressed at $t = 0$,the capacitor acts as a short circuit (uncharged). Thus,the entire voltage $2 \; V$ appears across the $100

Vedclass · Accepted Answer

At $t = 0, I = 2 \; mA$ and with time it decreases to $1 \; mA$

Vedclass · Answer

(C) When the key $K$ is pressed at $t = 0$,the capacitor acts as a short circuit (uncharged). Thus,the entire voltage $2 \; V$ appears across the $1000 \; \Omega$ resistor connected between $A$ and $B$.At $t = 0$,the current $I = \frac{V}{R} = \frac{2 \; V}{1000 \; \Omega} = 2 	imes 10^{-3} \; A = 2 \; mA$.As time passes,the capacitor charges. Once the capacitor is fully charged,it acts as an open circuit. The current then flows through both $1000 \; \Omega$ resistors in series.After a long time $(t 	o \infty)$,the equivalent resistance is $R_{eq} = 1000 \; \Omega + 1000 \; \Omega = 2000 \; \Omega$.The steady-state current is $I = \frac{V}{R_{eq}} = \frac{2 \; V}{2000 \; \Omega} = 1 	imes 10^{-3} \; A = 1 \; mA$.Therefore,at $t = 0, I = 2 \; mA$ and as time increases,it decreases to $1 \; mA$.

When the key $K$ is pressed at time $t = 0$,which of the following statements about the current $I$ in the resistor $AB$ of the given circuit is true?

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