When the current through a solenoid increases | vedclass

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(B) The magnetic flux $\phi$ through a solenoid is proportional to the current $I$ flowing through it, given by $\phi = LI$, where $L$ is the self-ind

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Is a constant and is opposite to the direction of the inducing current

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(B) The magnetic flux $\phi$ through a solenoid is proportional to the current $I$ flowing through it, given by $\phi = LI$, where $L$ is the self-inductance of the solenoid.According to Faraday's Law, the induced electromotive force $(EMF)$ is $\varepsilon = -\frac{d\phi}{dt} = -L \frac{dI}{dt}$.Since the current $I$ increases at a constant rate, $\frac{dI}{dt}$ is a positive constant.Therefore, the induced $EMF$ $\varepsilon = -L 	imes (	ext{constant})$ is a constant value.According to Lenz's Law, the direction of the induced current is such that it opposes the change in magnetic flux that produced it.Since the inducing current is increasing, the induced current will flow in the opposite direction to oppose this increase.

When the current through a solenoid increases at a constant rate, the induced current

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