When sulphanilic acid (p-H_2NC_6H_4SO_3H) is | vedclass

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(A) Sulphanilic acid $(p-H_2NC_6H_4SO_3H)$ contains a strongly activating amino group $(-NH_2)$ and a sulfonic acid group $(-SO_3H)$.In the presence o

Vedclass · Accepted Answer

tribromo product

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(A) Sulphanilic acid $(p-H_2NC_6H_4SO_3H)$ contains a strongly activating amino group $(-NH_2)$ and a sulfonic acid group $(-SO_3H)$.In the presence of water,the amino group is protonated to form the zwitterion $(H_3N^+C_6H_4SO_3^-)$.However,the $-NH_2$ group is highly activating and directs electrophilic substitution to the ortho positions.When treated with excess bromine water,the $-SO_3H$ group is displaced by bromine due to the high reactivity of the intermediate,leading to the formation of $2,4,6-tribromoaniline$.Therefore,the final product is a tribromo product.

When sulphanilic acid $(p-H_2NC_6H_4SO_3H)$ is treated with excess of bromine,the product is:

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