When subjected to a voltage of 10 , V, the cu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given: Voltage $V = 10 \, V$, initial current $I_1 = 0.1 \, A$, initial temperature $t_1 = 40^{\circ} C$, and temperature coefficient $\alpha = 2

Vedclass · Accepted Answer

$142$

Vedclass · Answer

(A) Given: Voltage $V = 10 \, V$, initial current $I_1 = 0.1 \, A$, initial temperature $t_1 = 40^{\circ} C$, and temperature coefficient $\alpha = 2 	imes 10^{-4} {}^{\circ} C^{-1}$.The initial resistance $R_1$ at $t_1 = 40^{\circ} C$ is $R_1 = \frac{V}{I_1} = \frac{10}{0.1} = 100 \, \Omega$.The resistance at temperature $t_2$ when the current $I_2 = 0.098 \, A$ is $R_2 = \frac{V}{I_2} = \frac{10}{0.098} \approx 102.04 \, \Omega$.Using the relation $R_2 = R_1 [1 + \alpha(t_2 - t_1)]$:$102.04 = 100 [1 + 2 	imes 10^{-4} (t_2 - 40)]$.$1.0204 = 1 + 2 	imes 10^{-4} (t_2 - 40)$.$0.0204 = 2 	imes 10^{-4} (t_2 - 40)$.$t_2 - 40 = \frac{0.0204}{2 	imes 10^{-4}} = 102$.$t_2 = 102 + 40 = 142^{\circ} C$.

Similar Questions

If the ammeter in the given figure shows a reading of $2 \, A$,find the value of $R$ in $\Omega$.

The current from the battery in the circuit diagram shown is .............. $A$.

The emf of a thermocouple,one junction of which is kept at $0\,^{\circ}C$,is given by $e = at + bt^2$. The Peltier coefficient will be

To verify Ohm's law,a student connects the voltmeter across the battery as shown in the figure. The measured voltage is plotted as a function of the current,and the following graph is obtained. If $V_0$ is almost zero,identify the correct statement.

$A$ bird sitting on a single high tension wire does not get electrocuted because

Vedclass Test Series

Exam Paper Generator

Online Exam Module