(C) The maximum kinetic energy of the ejected photoelectrons is related to the stopping potential $V_0$ by the equation: $K_{\max} = \frac{1}{2}mv_{\m

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(C) The maximum kinetic energy of the ejected photoelectrons is related to the stopping potential $V_0$ by the equation: $K_{\max} = \frac{1}{2}mv_{\max}^2 = eV_0$. Rearranging this equation to solve for the maximum velocity $v_{\max}$,we get: $v_{\max} = \sqrt{2(\frac{e}{m})V_0}$. Given values: $V_0 = 9 \ V$ and $\frac{e}{m} = 1.8 \times 10^{11} \ C \ kg^{-1}$. Substituting these values into the formula: $v_{\max} = \sqrt{2 \times (1.8 \times 10^{11}) \times 9}$. $v_{\max} = \sqrt{32.4 \times 10^{11}} = \sqrt{3.24 \times 10^{12}} = 1.8 \times 10^6 \ m \ s^{-1}$.

Class 12 Physics Dual Nature of Radiation and matter Einstein's Photoelectric Equation and Energy Quantum of Radiation

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When radiation is incident on a photoelectron emitter,the stopping potential is found to be $9 \ V$. If $e/m$ for the electron is $1.8 \times 10^{11} \ C \ kg^{-1}$,the maximum velocity of the ejected electrons is:

A
$6 \times 10^5 \ m \ s^{-1}$
B
$8 \times 10^5 \ m \ s^{-1}$
C
$1.8 \times 10^6 \ m \ s^{-1}$
D
$1.8 \times 10^5 \ m \ s^{-1}$

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Dual Nature of Radiation and matter

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Einstein's Photoelectric Equation and Energy Quantum of Radiation

In photoelectric effect,the graph of stopping potential $(V_0)$ versus frequency $(\nu)$ is a straight line. The slope of this graph is . . . . . . .

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$A$ photon of energy $8\,eV$ is incident on a metal surface of threshold frequency $1.6 \times 10^{15}\,Hz$. The maximum kinetic energy of photoelectrons emitted is .......... $eV$.
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When light of wavelength $\lambda$ is incident on a photosensitive surface,the stopping potential is $V$. When light of wavelength $3 \lambda$ is incident on the same surface,the stopping potential is $\frac{V}{6}$. Then the threshold wavelength for the surface is:

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When radiation is incident on a photoelectron emitter,the stopping potential is found to be $9 \ V$. If $e/m$ for the electron is $1.8 \times 10^{11} \ C \ kg^{-1}$,the maximum velocity of the ejected electrons is:

Similar Questions

In photoelectric effect,the graph of stopping potential $(V_0)$ versus frequency $(\nu)$ is a straight line. The slope of this graph is . . . . . . .

When a photosensitive surface is illuminated with light of wavelength $\lambda$,the stopping potential is $V$. When the same surface is illuminated by light of wavelength $2\lambda$,the stopping potential is $V/3$. The threshold wavelength for the surface is:

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$A$ photon of energy $8\,eV$ is incident on a metal surface of threshold frequency $1.6 \times 10^{15}\,Hz$. The maximum kinetic energy of photoelectrons emitted is .......... $eV$.(Take $h = 6.6 \times 10^{-34}\,J\cdot s$; $1\,eV = 1.6 \times 10^{-19}\,J$)

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$A$ photon of energy $8\,eV$ is incident on a metal surface of threshold frequency $1.6 \times 10^{15}\,Hz$. The maximum kinetic energy of photoelectrons emitted is .......... $eV$.
(Take $h = 6.6 \times 10^{-34}\,J\cdot s$; $1\,eV = 1.6 \times 10^{-19}\,J$)