Class 12Chemistry8-2.Carboxylic acids and Their derivativeProperties of Carboxylic Acids and Their Derivatives
MediumWhen propanoic acid is treated with aqueous sodium bicarbonate,carbon dioxide is liberated. The carbon of the $CO_2$ comes from :
- AMethyl group
- BCarboxylic group
- CMethylene group
- DBicarbonate
Explore More
Similar Questions
The decreasing order of nucleophilicity among the following nucleophiles is:
$(I)$ $CH_3-COO^{-}$
$(II)$ $CH_3O^{-}$
$(III)$ $C_6H_5O^{-}$
$(IV)$ $CH_3-SO_3^-$
$(I)$ $CH_3-COO^{-}$
$(II)$ $CH_3O^{-}$
$(III)$ $C_6H_5O^{-}$
$(IV)$ $CH_3-SO_3^-$
Difficult
View Solution$CH_3-C(=O)-O-CH_2-CH_3 + H-\bullet^- \to$ (where $\bullet = ^{18}O$) One of the products of the reaction is
Difficult
View SolutionThe major product formed in the following reaction is
$C_6H_5CH=CH_2$ $\xrightarrow[(ii) H_3O^+]{(i) KMnO_4, KOH, \Delta}$ $\xrightarrow{(iii) Br_2/FeBr_3} \text{Product}$
$C_6H_5CH=CH_2$ $\xrightarrow[(ii) H_3O^+]{(i) KMnO_4, KOH, \Delta}$ $\xrightarrow{(iii) Br_2/FeBr_3} \text{Product}$
What product is obtained when two moles of acetic acid are heated with $P_2O_5$?
Medium
View SolutionAcetic anhydride is obtained from acetyl chloride by the reaction of
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo