When phenol is treated with $PCl_5$,the yield of chlorobenzene is generally poor because of the formation of

  • A
    Benzoyl chloride
  • B
    $p-chlorophenol$
  • C
    $o-chlorophenol$
  • D
    Triphenyl phosphate

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What is the product formed when phenol reacts with concentrated $HNO_3$?

Benzene $+ CH_3CH_2CH_2Cl$ $\xrightarrow{AlCl_3} M$ $\xrightarrow{(i) O_2/\Delta , (ii) H_3O^+} N + \text{phenol}$. Here $M$ and $N$ are

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Given below are two statements:
Statement $I$: Bromination of phenol in solvent with low polarity such as $CHCl_3$ or $CS_2$ requires Lewis acid catalyst.
Statement $II$: The Lewis acid catalyst polarises the bromine to generate $Br^{+}$.
In the light of the above statements,choose the correct answer from the options given below:

Phenol $\xrightarrow[\Delta ]{Zn} A$ $\xrightarrow[\text{Anhydrous } AlCl_3]{CH_3Cl} B$ $\xrightarrow[\Delta ]{KMnO_4/OH^{-}} C$
The product $C$ is

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The major product of the following reaction is:

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