When Mendel self-hybridised the F_{1} plants | vedclass

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(D) In a dihybrid cross,Mendel crossed $F_{1}$ plants $(RrYy)$ with themselves. According to the law of independent assortment,the traits for each cha

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$3 : 1$ ratio

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(D) In a dihybrid cross,Mendel crossed $F_{1}$ plants $(RrYy)$ with themselves. According to the law of independent assortment,the traits for each character segregate independently. For a single character (e.g.,seed shape $Rr 	imes Rr$ or seed color $Yy 	imes Yy$),the phenotypic ratio of dominant to recessive traits in the $F_{2}$ generation is always $3:1$. Thus,for any one character,the dominant and recessive traits are segregated in a $3:1$ ratio.

When Mendel self-hybridised the $F_{1}$ plants $(RrYy)$,he found that dominant and recessive traits of one character are segregated in a

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