When light of wavelength 300 nm falls on a p | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The work function $\phi_0$ of a photoelectric emitter is related to the threshold wavelength $\lambda_0$ by the equation $\phi_0 = \frac{hc}{\lamb

Vedclass · Accepted Answer

$2 : 1$

Vedclass · Answer

(B) The work function $\phi_0$ of a photoelectric emitter is related to the threshold wavelength $\lambda_0$ by the equation $\phi_0 = \frac{hc}{\lambda_0}$.Given that the photoelectrons are just liberated,the incident wavelength is equal to the threshold wavelength.For the first emitter,$\lambda_{01} = 300 \ nm$.For the second emitter,$\lambda_{02} = 600 \ nm$.The ratio of the work functions is $\frac{\phi_{01}}{\phi_{02}} = \frac{hc / \lambda_{01}}{hc / \lambda_{02}} = \frac{\lambda_{02}}{\lambda_{01}}$.Substituting the values: $\frac{\phi_{01}}{\phi_{02}} = \frac{600 \ nm}{300 \ nm} = \frac{2}{1}$.Thus,the ratio is $2 : 1$.

When light of wavelength $300 \ nm$ falls on a photoelectric emitter,photoelectrons are just liberated. For another emitter,light of wavelength $600 \ nm$ is just sufficient for liberating photoelectrons. The ratio of the work function of the two emitters is

Similar Questions

Radiation of two photon energies,twice and five times the work function of a metal,are incident successively on the metal surface. The ratio of the maximum velocity of photoelectrons emitted in the two cases is:

From a metallic surface,photoelectric emission is observed for frequencies $v_1$ and $v_2$ $(v_1 > v_2)$ of the incident light. The maximum kinetic energy of the photoelectrons emitted in the two cases are in the ratio $1:x$. Hence,the threshold frequency of the metallic surface is

In photoelectric effect,the graph of stopping potential $(V_0)$ versus frequency $(\nu)$ is a straight line. The slope of this graph is . . . . . . .

The maximum wavelength of radiation that can produce the photoelectric effect in a certain metal is $200 \ nm$. The maximum kinetic energy acquired by an electron due to radiation of wavelength $100 \ nm$ will be .............. $eV$.

The work function of a metal is $6.825 \ eV$. Its threshold wavelength is approximately: (Given $c = 3 \times 10^8 \ m/s$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module