When isobutyl magnesium bromide in dry ether is treated with absolute ethyl alcohol,the products formed are

  • A
    $CH_3-CH(CH_3)-CH_2OH$ and $CH_3-CH_2-MgBr$
  • B
    $CH_3-CH(CH_3)-CH_2-CH_2-CH_3$ and $Mg(OH)Br$
  • C
    $CH_3-CH(CH_3)-CH_3$ and $CH_3-CH_2-OMgBr$
  • D
    $CH_3-CH(CH_3)-CH_3$,$CH_2=CH_2$ and $Mg(OH)Br$

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