When helium gas is allowed to expand into vac | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The Joule-Thomson effect describes the temperature change of a real gas as it is forced through a valve or porous plug while kept insulated so tha

Vedclass · Accepted Answer

The inversion temperature of helium is very low

Vedclass · Answer

(C) The Joule-Thomson effect describes the temperature change of a real gas as it is forced through a valve or porous plug while kept insulated so that no heat is exchanged with the environment.For most gases,expansion results in cooling because work is done to overcome intermolecular forces.However,for gases like $H_2$ and $He$,the inversion temperature is very low (for $He$,it is approximately $40 \ K$).If the gas temperature is above its inversion temperature during expansion,it exhibits a heating effect instead of cooling.Since the inversion temperature of $He$ is very low,it shows a heating effect under standard conditions.

When helium gas is allowed to expand into vacuum,a heating effect is observed. The reason for this is (assume $He$ as a non-ideal gas):

Similar Questions

At very high pressures,the compressibility factor of one mole of a gas is given by

At high temperature and low pressure,the Vander Waal's equation is reduced to

Which of the given sets of temperature and pressure will cause a gas to exhibit the greatest deviation from ideal gas behavior?

Pressure exerted by $1 \, mole$ of methane in a $0.25 \, L$ container at $300 \, K$ using van der Waals equation is ............... $atm$ (given $a = 2.253 \, atm \, L^2 \, mol^{-2}, b = 0.0428 \, L \, mol^{-1}$):

Identify the correct graph for an ideal gas ($y$-axis $= Z$; $x$-axis $= p$).

Vedclass Test Series

Exam Paper Generator

Online Exam Module