When heated in air,brown copper powder turns | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The correct option is $C$.When copper powder is heated in air,it reacts with oxygen to form copper$(II)$ oxide,which is black in color: $2Cu(s) +

Vedclass · Accepted Answer

$H_{2}$

Vedclass · Answer

(C) The correct option is $C$.When copper powder is heated in air,it reacts with oxygen to form copper$(II)$ oxide,which is black in color: $2Cu(s) + O_{2}(g) \stackrel{\Delta}{\longrightarrow} 2CuO(s)$ (Black).When this black copper$(II)$ oxide is heated with hydrogen gas $(H_{2})$,it undergoes a reduction reaction to form copper metal,which is brown in color: $CuO(s) + H_{2}(g) \stackrel{\Delta}{\longrightarrow} Cu(s) + H_{2}O(g)$.Thus,$H_{2}$ acts as a reducing agent to convert the black oxide back into brown copper.

When heated in air,brown copper powder turns black. This black powder would turn brown again when heated with:

Similar Questions

Statement $I$: Sodium hydride can be used as an oxidising agent.
Statement $II$: The lone pair of electrons on nitrogen in pyridine makes it basic.
Choose the $CORRECT$ answer from the options given below:

Which of the following reactions will not occur?

Which substance is serving as a reducing agent in the following reaction: $14H^{+} + Cr_2O_7^{2-} + 3Ni \to 2Cr^{3+} + 7H_2O + 3Ni^{2+}$?

Which of the following oxidizing agents is used as an antiseptic?

Which of these substances is a good reducing agent?

Vedclass Test Series

Exam Paper Generator

Online Exam Module