(C) For a diatomic gas of rigid molecules,the molar heat capacity at constant volume is $C_V = \frac{5}{2} R$.Given that heat $Q$ is supplied at const

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(C) For a diatomic gas of rigid molecules,the molar heat capacity at constant volume is $C_V = \frac{5}{2} R$.Given that heat $Q$ is supplied at constant volume,we have $Q = n C_V \Delta T = n (\frac{5}{2} R) \Delta T$.For the same change in temperature $\Delta T$ at constant pressure,the heat required is $Q' = n C_P \Delta T$,where $C_P = \frac{7}{2} R$.Taking the ratio,we get $\frac{Q'}{Q} = \frac{n C_P \Delta T}{n C_V \Delta T} = \frac{C_P}{C_V} = \frac{7/2 R}{5/2 R} = \frac{7}{5}$.Therefore,$Q' = \frac{7}{5} Q$.

Class 11 Physics Kinetic Theory of Gases Molar Specific Heat of gas and relation between them (Mayer's formula)

Medium

When heat $Q$ is supplied to a diatomic gas of rigid molecules at constant volume,its temperature increases by $\Delta T$. The heat required to produce the same change in temperature at constant pressure is:

JEE MAIN 2019 All JEE MAIN

A
$\frac{3}{2} Q$
B
$\frac{5}{3} Q$
C
$\frac{7}{5} Q$
D
$\frac{2}{3} Q$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Physics Questions

Chapter

Kinetic Theory of Gases

Subtopic

Molar Specific Heat of gas and relation between them (Mayer's formula)

Previous Year

JEE MAIN 2019 Paper All JEE MAIN years →

For all gases,$C_P - C_V$ is a constant. Does this imply that for all gases,$\frac{C_P}{C_V}$ is also a constant?

Easy

View Solution

The relation $C_p - C_V = R$ ($C_p$ and $C_V$ are the molar specific heats at constant pressure and volume) is exactly true for

MediumKVPY 2009

View Solution

The specific heat of helium at constant volume is $12.6 \,J \,mol^{-1} \,K^{-1}$. The specific heat of helium at constant pressure in $J \,mol^{-1} \,K^{-1}$ is approximately (assume,the universal gas constant,$R=8.314 \,J \,mol^{-1} \,K^{-1}$)

EasyTS EAMCET 2020

View Solution

Identify the correct relationship between the molar heat capacities of an ideal gas.

Medium

View Solution

The specific heat at constant volume for the monoatomic argon is $0.075 \, kcal/kg-K$,whereas its gram molecular specific heat $C_V = 2.98 \, cal/mole/K$. The mass of the argon atom is (Avogadro's number $= 6.02 \times 10^{23} \, molecules/mole$)

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

When heat $Q$ is supplied to a diatomic gas of rigid molecules at constant volume,its temperature increases by $\Delta T$. The heat required to produce the same change in temperature at constant pressure is:

Similar Questions

For all gases,$C_P - C_V$ is a constant. Does this imply that for all gases,$\frac{C_P}{C_V}$ is also a constant?

The relation $C_p - C_V = R$ ($C_p$ and $C_V$ are the molar specific heats at constant pressure and volume) is exactly true for

The specific heat of helium at constant volume is $12.6 \,J \,mol^{-1} \,K^{-1}$. The specific heat of helium at constant pressure in $J \,mol^{-1} \,K^{-1}$ is approximately (assume,the universal gas constant,$R=8.314 \,J \,mol^{-1} \,K^{-1}$)

Identify the correct relationship between the molar heat capacities of an ideal gas.

The specific heat at constant volume for the monoatomic argon is $0.075 \, kcal/kg-K$,whereas its gram molecular specific heat $C_V = 2.98 \, cal/mole/K$. The mass of the argon atom is (Avogadro's number $= 6.02 \times 10^{23} \, molecules/mole$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module