When ethyl chloride and alcoholic KOH are hea | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction between ethyl chloride $(CH_3CH_2Cl)$ and alcoholic $KOH$ is a dehydrohalogenation reaction. In this reaction,an elimination process

Vedclass · Accepted Answer

$C_2H_4$

Vedclass · Answer

(A) The reaction between ethyl chloride $(CH_3CH_2Cl)$ and alcoholic $KOH$ is a dehydrohalogenation reaction. In this reaction,an elimination process occurs where a hydrogen atom and a chlorine atom are removed from adjacent carbon atoms to form an alkene. The chemical equation for the reaction is: $CH_3CH_2Cl + KOH (	ext{alc.}) ightarrow CH_2=CH_2 + KCl + H_2O$. Thus,the product obtained is ethene $(C_2H_4)$.

When ethyl chloride and alcoholic $KOH$ are heated,the compound obtained is

Similar Questions

Which of the following reagents,when heated with ethyl chloride,forms ethylene?

What will be the reduction products of the following reactions:
$CHCl_3 \xrightarrow[Zn/HCl \text{ (alc.)}]{+2H}$
$CHCl_3 \xrightarrow[Zn/HCl \text{ (aq.)}]{+4H}$
$CHCl_3 \xrightarrow[Zn/H_2O]{+6H}$

The major product of the above reaction is:

Elimination of bromine from $2-$bromobutane results in the formation of

Which one among the following will undergo a faster $S_{N}1$ reaction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module