(A) $Cu$ is placed above $Ag$ in the electrochemical series,hence it can displace $Ag$ from its salt solution.The reaction is: $Cu(s) + 2AgNO_3(aq) \r

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(A) $Cu$ is placed above $Ag$ in the electrochemical series,hence it can displace $Ag$ from its salt solution.The reaction is: $Cu(s) + 2AgNO_3(aq) \rightarrow Cu(NO_3)_2(aq) + 2Ag(s)$.In this reaction,$Cu$ loses electrons to form $Cu^{2+}$ ions,which is an oxidation process $(Cu^0 \rightarrow Cu^{2+} + 2e^-)$.