When aniline reacts with $NaNO_2$ and dil. $HCl$ at $0^{\circ} - 5^{\circ}C,$ the product formed is

$Methyl$ amine on reaction with chlorine in the presence of $NaOH$ gives:

Identify the reagent $R$ in the following reaction:
$C_6H_5NO_2 \xrightarrow{R} C_6H_5NHOH$

The reaction of $N$-phenylbenzamide with $NO_2^{\oplus}$ (nitronium ion) yields which product?

Complete the following acid-base reactions and name the products:
$(i)$ $CH_{3}CH_{2}CH_{2}NH_{2} + HCl \rightarrow$
$(ii)$ $(C_{2}H_{5})_{3}N + HCl \rightarrow$

Aniline reacts with mixed acid (conc. $HNO_3$ and conc. $H_2SO_4$) at $288 \ K$ to give $P$ $(51 \%)$,$Q$ $(47 \%)$ and $R$ $(2 \%)$. The major product$(s)$ of the following reaction sequence is (are):
$R$ $\xrightarrow[2) Br_2, CH_3CO_2H]{1) Ac_2O, \text{pyridine}}$ $\xrightarrow{3) H_3O^+}$ $\xrightarrow{4) NaNO_2, HCl / 273-278 \ K}$ $\xrightarrow{5) EtOH, \Delta}$ $\xrightarrow{6) Sn/HCl}$ $\xrightarrow{7) Br_2/H_2O \text{ (excess)}} \text{Major Product}$