When an object of height 12 cm is placed at | vedclass

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(C) Let the height of the object be $h_0 = 12 \ cm$. When the lens is placed at the first position,the image height is $h_1 = 18 \ cm$. When the lens

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(C) Let the height of the object be $h_0 = 12 \ cm$. When the lens is placed at the first position,the image height is $h_1 = 18 \ cm$. When the lens is moved to the second position,the image height is $h_2$. According to the displacement method for a convex lens,the relationship between the object height and the two image heights is given by the formula: $h_0 = \sqrt{h_1 \cdot h_2}$ Substituting the given values: $12 = \sqrt{18 \cdot h_2}$ Squaring both sides: $144 = 18 \cdot h_2$ $h_2 = \frac{144}{18} = 8 \ cm$. Thus,the height of the second image is $8 \ cm$.

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