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(B) The heat supplied at constant pressure is given by $Q_p = n C_p \Delta T$.The change in internal energy is given by $\Delta U = n C_v \Delta T$.Th

Vedclass · Accepted Answer

$0.75$

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(B) The heat supplied at constant pressure is given by $Q_p = n C_p \Delta T$.The change in internal energy is given by $\Delta U = n C_v \Delta T$.The fraction of heat energy used to increase the internal energy is $f = \frac{\Delta U}{Q_p} = \frac{n C_v \Delta T}{n C_p \Delta T} = \frac{C_v}{C_p} = \frac{1}{\gamma}$.For an ideal non-linear triatomic gas,the degrees of freedom $f_{deg} = 6$.The adiabatic index $\gamma = 1 + \frac{2}{f_{deg}} = 1 + \frac{2}{6} = 1 + \frac{1}{3} = \frac{4}{3}$.Therefore,the fraction $f = \frac{1}{4/3} = \frac{3}{4} = 0.75$.

When an ideal triatomic non-linear gas is heated at constant pressure,the fraction of the heat energy supplied which increases the internal energy of the gas is

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