When an electron makes a transition from $n=4$ to $n=2$,the emitted line spectrum will be:

  • A
    first line of Lyman series
  • B
    first line of Paschen series
  • C
    second line of Balmer series
  • D
    second line of Paschen series

Explore More

Similar Questions

Explain the transition between energy levels in an atom by drawing a line spectra diagram.

When the electron in the hydrogen atom jumps from the $2^{nd}$ orbit to the $1^{st}$ orbit,the wavelength of the radiation emitted is $\lambda$. When the electron jumps from the $3^{rd}$ orbit to the $1^{st}$ orbit,the wavelength of the emitted radiation will be:

Difficult
View Solution

The stopping potential for the photoelectrons emitted from a metal surface of work function $1.7 \ eV$ is $10.4 \ V$. Identify the energy levels corresponding to the transitions in a hydrogen atom which will result in the emission of a wavelength equal to that of the incident radiation for the above photoelectric effect.

The transition of an electron in a hydrogen atom that emits a photon whose wavelength lies in the ultraviolet region of the electromagnetic spectrum is

Which spectral series of the hydrogen atom is found in the ultraviolet region?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo