When an a.c. source is connected across a pure resistor,the correct phase relation between current $(i_R)$ and voltage $(e_R)$ is shown in which figure?

If the capacitance of a pure capacitor in a $DC$ circuit is $1 \ F$,then what will be its capacitive reactance?

For obtaining wattless current . . . . . . is connected with ac supply.

$A$ capacitor of $50 \mu F$ is connected to an a.c. source $e = 220 \sin(50t)$ (where $e$ is in volts and $t$ is in seconds). The value of the peak current is:

Given below are two statements:
Statement-$I$: In an $AC$ circuit,the current through a capacitor leads the voltage across it.
Statement-$II$: In $AC$ circuits containing pure capacitance only,the phase difference between the current and the voltage is $\pi$.
In the light of the above statements,choose the most appropriate answer from the options given below:

If we increase the frequency of an $a.c.$ supply,then inductive reactance