When acidified KMnO_4 is added to hot oxalic | vedclass

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Question

(A) The reaction between acidified $KMnO_4$ and oxalic acid is given by: $2MnO_4^- + 5H_2C_2O_4 + 6H^+ \rightarrow 2Mn^{2+} + 10CO_2 + 8H_2O$. In this

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$Mn^{2+}$ acts as autocatalyst

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(A) The reaction between acidified $KMnO_4$ and oxalic acid is given by: $2MnO_4^- + 5H_2C_2O_4 + 6H^+ \rightarrow 2Mn^{2+} + 10CO_2 + 8H_2O$. In this reaction,$Mn^{2+}$ ions are produced as a product. These $Mn^{2+}$ ions act as an autocatalyst,meaning they increase the rate of the reaction as their concentration increases. Therefore,the reaction is slow initially but becomes rapid as the concentration of $Mn^{2+}$ increases.

When acidified $KMnO_4$ is added to hot oxalic acid solution,the decolourization is slow in the beginning,but becomes very rapid after some time. This is because :

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