When acidified K_2Cr_2O_7 reacts with H_2O_2, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Step $I$: Acidification of potassium dichromate: $K_2Cr_2O_7 + H_2SO_4 \rightarrow K_2SO_4 + H_2Cr_2O_7$Step $II$: Reaction with hydrogen peroxide

Vedclass · Accepted Answer

$CrO_5$

Vedclass · Answer

(D) Step $I$: Acidification of potassium dichromate: $K_2Cr_2O_7 + H_2SO_4 \rightarrow K_2SO_4 + H_2Cr_2O_7$Step $II$: Reaction with hydrogen peroxide: $H_2Cr_2O_7 + 4H_2O_2 \rightarrow 2CrO_5 + 5H_2O$Step $III$: The overall balanced chemical equation is $K_2Cr_2O_7 + H_2SO_4 + 4H_2O_2 \rightarrow 2CrO_5 + K_2SO_4 + 5H_2O$The blue colour is due to the formation of chromium$(VI)$ peroxide,which is $CrO_5$. This compound is unstable and decomposes rapidly in aqueous solution,but it exhibits a characteristic deep blue colour.Hence,the correct option is $D$.

When acidified $K_2Cr_2O_7$ reacts with $H_2O_2$,a blue-coloured solution is obtained. This blue colour is due to the formation of:

Similar Questions

Zinc forms two important alloys,$(i)$ Brass and $(ii)$ German silver. Metals present in them mainly are

The oxoanion in which the oxidation state of the central atom is same as its group number in the periodic table is

What is obtained when gold chloride is heated?

Which pair of elements from the following is used to make an alloy for trophies?

Which of the following statements is incorrect?

Vedclass Test Series

Exam Paper Generator

Online Exam Module