When acetylene is reacted with HBr,we get | vedclass

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(D) The reaction of acetylene $(CH \equiv CH)$ with $HBr$ proceeds via electrophilic addition.First,one molecule of $HBr$ adds to acetylene to form vi

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Ethylidene bromide

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(D) The reaction of acetylene $(CH \equiv CH)$ with $HBr$ proceeds via electrophilic addition.First,one molecule of $HBr$ adds to acetylene to form vinyl bromide $(CH_2 = CHBr)$.Then,a second molecule of $HBr$ adds to the vinyl bromide following Markovnikov's rule to form ethylidene dibromide $(CH_3CHBr_2)$.The reaction is: $CH \equiv CH$ $\xrightarrow{HBr} CH_2 = CHBr$ $\xrightarrow{HBr} CH_3CHBr_2$.

When acetylene is reacted with $HBr$,we get

Similar Questions

Identify the alkyne in the following sequence of reactions:
Alkyne $\xrightarrow{\text{H}_2, \text{Lindlar's catalyst}} A$ $\xrightarrow{\text{Ozonolysis}} B \text{ (only)}$
Given that $B$ is obtained from $\text{CH}_2=\text{CH}_2$ via the Wacker process.

The reagent$(s)$ for the following conversion is/are:
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Which of the following will produce a chiral molecule after treatment with $H_2$/Lindlar's catalyst?

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